BuyQualityEssays.com – ORDER 100% ANSWERED QUESTION…Determine the quantity (g) of pure MgSO4 in 2.4 g of MgSO4•7H2O. Show your work.

Determine the quantity (g) of pure MgSO4 in 2.4 g of MgSO4•7H2O. Show your work.
Molar mass of MgSO4 = 120.366 g/mol
 
Molar mass of MgSO4.7H20 = 120.366+(7*18) = 246
 
quantity of pure MgSO4 in 2.4 g of MgSO4*7H2O = (Molar mass MgSO4)/(Molar mass MgSO4.7H20) * 2.4 =1.1743 g
 
1.17 g of Pure MgSO4  is in 2.4 g of MgSO4•7H2O
 
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